Question
Construct a quadrilateral ABCD in which AB = BC = 6cm, AD = DC = 4.5cm and $\angle\text{B}=120^\circ.$
✓
Answer
Steps of construction:Step I: Draw AB = 6cm.
Step II: Construct $\angle\text{ABC}=120^\circ.$
Step III: With B as the centre and radius 6cm, cut off BC = 6 cm. Now, we can see that AC is about 10.3cm which is greater than AD + CD = 4.5 + 4.5 = 9cm.
We know that sum of the lengths of two sides of triangle is always greater than the third side but here, the sum of AD and CD is less than AC.
So, construction of the given quadrilateral is not possible.
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