Question
Construct a quadrilateral $\text{ABCD}$ in which $AD = AB = 5\ cm, BC = 3.8\ cm, CD = 3.5\ cm$, and $\angle BAD = 45^\circ $
✓
Answer
$AD = AB = 5\ cm, BC = 3.8\ cm, CD = 3.5\ cm$, and $\angle BAD = 45^\circ $
Steps of Construction:
$1)$ Draw a line segment $AB = 5\ cm.$
$2)$ With $A$ as centre draw an angle an angle of $90^\circ $ and bisect it from $\angle BAD = 45^\circ $
$3)$ With $A$ as centre and radius $5\ cm$ cut an arc on the ray making an angle of $45^\circ $ with $AB$ and mark it $D.$
$4)$ With $D$ and $B$ as centre and radii as $3.5\ cm$ and $3.8\ cm$ respectively draw arcs intersecting each other at $C.$
$5)$ Join $DC$ and $BC.$
$6)\text{ABCD}$ is the required quadrilateral.
Steps of Construction:
$1)$ Draw a line segment $AB = 5\ cm.$
$2)$ With $A$ as centre draw an angle an angle of $90^\circ $ and bisect it from $\angle BAD = 45^\circ $
$3)$ With $A$ as centre and radius $5\ cm$ cut an arc on the ray making an angle of $45^\circ $ with $AB$ and mark it $D.$
$4)$ With $D$ and $B$ as centre and radii as $3.5\ cm$ and $3.8\ cm$ respectively draw arcs intersecting each other at $C.$
$5)$ Join $DC$ and $BC.$
$6)\text{ABCD}$ is the required quadrilateral.
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