Question
Construct a quadrilateral $ABCD$ in which ; $\angle A = 120^\circ , \angle B = 60^\circ , AB = 4 \ cm, BC = 4.5 \ cm$ and $CD = 5 \ cm.$
✓
Answer
The rough figure is as follow :
The Actual figure is constructed as follow
Steps :
The Actual figure is constructed as follow
Steps :
- Draw $AB = 4 \ cm.$
- At $A$, draw $\angle PAB = 120^\circ .$
- At $B$, draw $\angle QBA = 60^\circ $.
- From $BQ$, cut $BC = 4.5 \ cm.$
- From $C$, draw an arc of radius $5 \ cm$ which meets $AP $ at $D.$
- Join $CD.$
Thus $ABCD$ is the required quadrilateral.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
For each set of rational number, given below, verify the associative property of addition of rational number: $(i)$ $-1, \frac{5}{6}$ and $\frac{-2}{3}$
→Solve : $15 – 2(2x – 1) < 15, x \in Z.$
→Expand : $(a+b−c)^2$
→Evaluate : $(4x^2 − 5y^2) (4x^2 + 5y^2)$
→If $a + b + c = 11$ and $a^2 + b^2 + c^2 = 81,$ find $: ab + bc + ca.$
→Evaluate: $(9 − y) (7 + y)$
→The numerator of a fraction is $5$ less than its denominator. If $3$ is added to the numerator, and denominator both, the fraction becomes $\frac{2}{3}$. Find the original fraction.
→Find a single discount $($as a percent$)$ equivalent to following successive discounts: $20\%$ and $12\%$
→Find the value of :
$\frac{\sqrt{1183}}{\sqrt{2023}}$
→$\frac{\sqrt{1183}}{\sqrt{2023}}$
A number decreased by $30$ is the same as $14$ decreased by $3$ times the number; Find the number.
→