Question
Construct a square, each of whose diagonals measures 5.8cm.
✓
Answer
We know that the diagonals of a square bisect each other at right angles.
Steps of construction: Step 1: Draw AC = 5.8cm. Step 2: Draw the perpendicular bisector XY of AC, meeting it at O. Step 3: From O: $\text{OB}=\frac{1}{2}(5.8)\text{cm}=2.9\text{cm}$ $\text{OD}=\frac{1}{2}(5.8)\text{cm}=2.9\text{cm}$ Step 4: Join AB, BC, CD and DA. ABCD is the required square.
Steps of construction: Step 1: Draw AC = 5.8cm. Step 2: Draw the perpendicular bisector XY of AC, meeting it at O. Step 3: From O: $\text{OB}=\frac{1}{2}(5.8)\text{cm}=2.9\text{cm}$ $\text{OD}=\frac{1}{2}(5.8)\text{cm}=2.9\text{cm}$ Step 4: Join AB, BC, CD and DA. ABCD is the required square.
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