Question
Construct a trapezium ABCD in which AB = 6cm, BC = 4cm, CD = 3.2cm, $\angle\text{B}=75^\circ$ and DC || AB.
✓
Answer
Steps of construction:Step 1: Draw AB=6 cm.
Step 2: Make $\angle\text{ABX}=75^\circ$
Step 3: With B as the centre, draw an arc at 4cm. Name that point as C.
Step 4: AB || CD
$\therefore\angle\text{ABX}+\angle\text{BCY}=180^\circ$
$\Rightarrow\angle\text{BCY}=180^\circ-75^\circ=105^\circ$
Make $\angle\text{BCY}=105^\circ$
At C, draw an arc of length 3.2cm.
Step 5: Join A and D.
Thus, ABCD is the required trapezium.
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