Question
Construct a triangle using the given data: $PQ = 4.8\ cm, QR = 6.3\ cm$ and $PR = 5.5\ cm$
✓
Answer
$PQ = 4.8\ cm, QR = 6.3\ cm$ and $PR = 5.5\ cm$
Steps of Construction:
$1.$ Draw $PQ = 4.8\ cm$
$2.$ With $P$ as centre and radius $5.5\ cm$, draw an arc.
$3.$ With $Q$ as centre and radius $6.3\ cm$, draw another arc to cut the first arc at $R.$
$4.$ Join $PR$ and $QR.$
Thus, $\text{PQR}$ is the required triangle.
Steps of Construction:
$1.$ Draw $PQ = 4.8\ cm$
$2.$ With $P$ as centre and radius $5.5\ cm$, draw an arc.
$3.$ With $Q$ as centre and radius $6.3\ cm$, draw another arc to cut the first arc at $R.$
$4.$ Join $PR$ and $QR.$
Thus, $\text{PQR}$ is the required triangle.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The following data have been arranged in ascending order. If their median is $63,$ find the value of $x.34, 37, 53, 55, x, x + 2, 77, 83, 89$ and $100.$
→Evaluate : $(64)^{\frac{2}{3}}-\sqrt[3]{125}-\frac{1}{2^{-5}}+(27)^{-\frac{2}{3}} \times\left(\frac{25}{9}\right)^{-\frac{1}{2}} \mathrm{}$
→The cost of manufacturing $x$ articles is $Rs.(50 + 3x)$. The selling price of $x$ articles is $Rs. 4x.$On a graph sheet, with the same axes, and taking suitable scales draw two graphs, first for the cost of manufacturing against no. of articles and the second for the selling price against the number of articles.Use your graph to determine:The profit or loss made when $(a) 30\ (b) 60$ articles are manufactured and sold.
→The radii of two circles are in the ratio $3: 8$. If the difference between their areas is $2695\pi ~cm^2$, find the area of the smaller circle.
→A chord of length $8 \ cm$ is drawn at a distance of $3 \ cm$ from the center of the circle.Calculate the radius of the circle.
→Solve graphically, the following equations. $x + 2y = 4; 3x - 2y = 4.$ Take $2 \ cm = 1$ unit on each axis.Also, find the area of the triangle formed by the lines and the $x-$ axis.
→Calculate the area of quadrilateral ABCD in which :
$\begin{array}{l}AB=24 cm, AD=32 cm, \angle BAD=90 \\
\text { and } BC=CD=52 cm\end{array}$.
→$\begin{array}{l}AB=24 cm, AD=32 cm, \angle BAD=90 \\
\text { and } BC=CD=52 cm\end{array}$.
Solve the following systems of equation by using the method of cross multiplication:
$2 x+5 y=1,2 x+3 y=3$
→$2 x+5 y=1,2 x+3 y=3$
Solve the following pair of linear (simultaneous) equation using method of elimination by substitution$:3x + 2y =11,2x - 3y + 10 = 0$
→In an isosceles $ \triangle ABC, AB = BC = 6 \ cm$ and $\angle B = 90^\circ $. Find the values of $\cos C$
→