Question
Construct a $\triangle\text{ABC}$ in which BC = 3.6cm, AB + AC = 4.8cm and $\angle\text{B}=60^\circ. $
✓
Answer
Steps of Construction:
- Construct a line segment BC of 3.6cm.
- At the point B, draw $\angle\text{XBC}=60^\circ.$
- Keeping B as center and radius 4.8cm draw an arc which intersects XB at D.
- Join DC.
- Draw the perpendicular bisector of DC which intersects DB at A.
- Join AC.
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