Question
Construct $\angle\text{AOB}=85^\circ$ with the help of a protractor. Draw a ray OX bisecting $\angle\text{AOB}.$
✓
Answer
Steps for construction:
- Draw $\angle\text{AOB}=85^\circ$ with the help of a protractor.
- With O as the centre and any convenient radius, draw an arc cutting OA and OB at P and Q, respectively.
- With P as the centre and radius more than half of PQ, draw an arc.
- With Q as the centre and the same radius as before, draw another arc cutting the previously drawn arc at a point R.
- Draw RO and produce it to point X.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Write all the factors of the given numbers and list their common factors:
i. 12, 16
ii. 21, 24
iii. 25, 30
iv. 24, 25
v. 56, 72
i. 12, 16
ii. 21, 24
iii. 25, 30
iv. 24, 25
v. 56, 72
The length and breadth of a rectangular park are in the ratio $5 : 3$ and its perimeter is $128\ m$. Find the area of the park.
→The pictograph shown different subject books which are kept in a library.
- How many English books are there in the library?
- How many maths books are there?
- Which books are maxmimum in number?
- Which books are minimum in number?
Write the number of faces, edges and vertices of each shape in the table.
The number of girl students in each class of co-ed. Middle school is depicted by the following pictograph:
Observe the above pictograph and answer the following questions:
Observe the above pictograph and answer the following questions:
- Which class has the maximum number of girl students?
- Is the number of girls in class VI is less than the number of girls in class V?
- How many girls are there in VII class?
Use a pair of compasses and construct the following angles:
$67\frac{1}{2}^\circ$
→$67\frac{1}{2}^\circ$
Match the following columns on whole numbers:
|
S.No.
|
Column A
|
S.No.
|
Column B
|
|
(a)
|
137 + 63 = 63 + 137
|
(i)
|
Associativity of multiplication
|
|
(b)
|
(16 × 25) is a number
|
(ii)
|
Commutativity of multiplication
|
|
(c)
|
365 × 18 = 18 × 365
|
(iii)
|
Distributive law of multiplication over addition.
|
|
(d)
|
(d) (86 × 14) × 25 = 86 × (14 × 25)
|
(iv)
|
Commutativity of addition
|
|
(e)
|
23 × (80 + 5) = (23 × 80) + (23 × 5)
|
(v)
|
Closure property for multiplication
|
Read the following bar graph and answer the following questions:
- What information is given by the bar graph?
- In which year the export is minimum?
- In which year the import is maximum?
- In which year the difference of the value of export and import is maximum?
(1) $6 \frac{1}{3}+2 \frac{1}{3}$
(2) $1 \frac{1}{4}+3 \frac{1}{2}$
(3) $5 \frac{1}{5}+2 \frac{1}{7}$
(4) $3 \frac{1}{5}+2 \frac{1}{3}$
→(2) $1 \frac{1}{4}+3 \frac{1}{2}$
(3) $5 \frac{1}{5}+2 \frac{1}{7}$
(4) $3 \frac{1}{5}+2 \frac{1}{3}$
A rectangular courtyard is 18m, 72cm long and 13m, 20cm board. It is to be paved with square tiles of the same size. Find the least possibele number of such tiles.