Question
Construct the following indices by taking 2014 as the base year
  1. Simple Aggregative Price Index.
  2. Index of Average of Price Relative.
Item
A
B
C
D
E
Price in 2014 (₹)
6
2
4
10
8
Price in 2015 (₹)
10
2
6
12
12
Price in 2016 (₹)
15
3
8
14
16

Answer

Construction of Index number:
Item
Price in 2014 (₹)
Price in 2015 (₹)
Price in 2016 (₹)
$\text{I}\bigg(\frac{\text{p}_1}{\text{p}_0}\times100\bigg)$
$\text{I}_2\bigg(\frac{\text{p}_2}{\text{p}_0}\times100\bigg)$
A
6
10
15
166.67
250
B
2
2
3
100.00
150
C
4
6
8
150.00
200
D
10
12
12
120.00
140
E
8
12
16
150.00
200
n = 5
$\Sigma\text{p}_0=30$
$\Sigma\text{p}_1=42$
$\Sigma\text{p}_2=56$
$\Sigma\text{I} _1=686.67$
$\Sigma\text{I}_2=940$
  1. Simple Aggregative Price Index:
$\text{P}_{01}=\frac{\Sigma\text{p}_1}{\Sigma\text{p}_0}\times100=\frac{42}{30}\times100=140(\text{for 2015}),$

$\text{p}_{02}=\frac{\Sigma\text{p}_2}{\Sigma\text{p}_0}\times100=\frac{56}{30}\times100=186.67(\text{for 2016})$
  1. Index of Avrege of Price Relative:
$\text{p}_{01}=\frac{\Sigma\text{I}_1}{\text{n}} =\frac{686.67}{5}=137.34(\text{for 2015}),$

$\text{p}_{02}=\frac{\Sigma\text{I}_2}{\text{n}}=\frac{940}{5}=188(\text{for 2016})$

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