MCQ
$Co|Co^{2+}(C_2)||Co^{2+}(C_1)|Co$, for this cell, $\Delta G$ is negative if
- A$C_2 > C_1$
- ✓$C_2 < C_1$
- C$C_1 = C_2$
- Dunpredictable
✓
Answer
Correct option: B.
$C_2 < C_1$
b
$\mathrm{E}_{\text {cell }}=\mathrm{E}_{\text {cell }}^{\circ}-\frac{0.059}{\mathrm{n}} \log \frac{\mathrm{C}_{2}}{\mathrm{C}_{1}}$
$\mathrm{E}_{\text {cell }}=\mathrm{E}_{\text {cell }}^{\circ}-\frac{0.059}{\mathrm{n}} \log \frac{\mathrm{C}_{2}}{\mathrm{C}_{1}}$
For concentration cell $\mathrm{E}_{\text {cell }}^{o}=0$
$\mathrm{E}_{\text {cell }}=-\frac{0.059}{\mathrm{n}} \log \frac{\mathrm{C}_{2}}{\mathrm{C}_{1}}$
$\Delta G=$ negative ie $E_{\text {cell }}=$ positive For $E_{\text {cell }}$ positive $=C_{1}>C_{2}$
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