MCQ
Copper cannot replace….. from solution
- ✓$Fe$
- B$Au$
- C$Hg$
- D$Ag$
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Atomic weight : $Fe =55.85 ; \mathrm{S}=32.0$ $\mathrm{O}=16.00$
$CH_3 -C\equiv C-H$ $\xrightarrow{{C{H_3}MgBr}}$ $CH_4+(A)$ $\mathop {\xrightarrow{{(i)\,C{O_2}}}}\limits_{(ii)\,{H_2}O/{H^ \oplus }} $ $(B)$
$(B)$ will be :
