MCQ
Copper sulphate solution reacts with $KCN$ to give
- A$Cu{(CN)_2}$
- B$CuCN$
- C${K_2}[Cu{(CN)_4}]$
- ✓${K_3}[Cu{(CN)_4}]$
✓
Answer
Correct option: D.
${K_3}[Cu{(CN)_4}]$
d
(d) $CuS{O_4} + 2KCN \to Cu{(CN)_2} + {K_2}S{O_4}$
(d) $CuS{O_4} + 2KCN \to Cu{(CN)_2} + {K_2}S{O_4}$
$2Cu{(CN)_2} \to C{u_2}{(CN)_2} + {(CN)_2}$
$C{u_2}{(CN)_2} + 6KCN \to 2{K_3}[Cu{(CN)_4}]$
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