Question
Correct order of acidic strength
✓
Answer
b
Substance can acts as both oxidizing as well as reducing agent when a metal atom is present in its intermediate step.
Substance can acts as both oxidizing as well as reducing agent when a metal atom is present in its intermediate step.
$O _3$ can acts as only oxidizing agent due to its unstable nature and decomposes to give nascent oxygen.
$HNO _3$ : Nitrogen is present in its highest oxidation state i.e., $+5$ so it can act as only oxidizing agent.
$SO _2$ :Sulphur is present in $+4$ oxidation state so it can act as both oxidizing as well as reducing agent.
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In the reaction
→$\begin{array}{*{20}{c}}
{\,\,\,C{H_3}{\mkern 1mu} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} } \\
{\,\,|{\mkern 1mu} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} } \\
{C{H_3} - CH - C{H_2} - O - C{H_2} - C{H_3} + HI\xrightarrow{{Heated}}{\mkern 1mu} ..........}
\end{array}$
Which of the following compounds will be formed ?
The telluric helix was given by
$10$ moles of an ideal gas confined to a volume of $10\,L$ is released into atmosphere at $300\, K$ where the pressure is $1\, bar.$ The work done by the gas is ....$L\, bar$
→$(R = 0.083\, L\, bar\, K^{-1} \,mol^{-1})$
The order of stability of the following carbocations is :
→$(I)\,\,C{H_2} = CH - \mathop C\limits^ \oplus {H_2}$
$(II)\,\,C{H_3} - CH_2 - \mathop C\limits^ \oplus {H_2}$
When $3$ mole of $A$ and $1$ mole of $B$ are mixed in $1$ litre vessel the following reaction takes place ${A_{(g)}} + {B_{(g)}}$ $\rightleftharpoons$ $2{C_{(g)}}$. $1.5$ moles of $ C$ are formed. The equilibrium constant for the reaction is
→Moles of $K_2Cr_2O_7$ used to oxidise $1$ $mole$ $Fe_{0.92}O$ to $Fe^{3+}$ are -
→If $S + {O_2} \to S{O_2};\,(\Delta H = - 298.2)$ $S{O_2} + \frac{1}{2}{O_2} \to S{O_3};\,(\Delta H = - 98.2)$$S{O_3} + {H_2}O \to {H_2}S{O_4};\,(\Delta H = - 130.2)$ ${H_2} + \frac{1}{2}{O_2} \to {H_2}O;\,(\Delta H = - 287.3)$ then the enthalpy of formation of ${H_2}S{O_4}$ at $298\,K $ will be......$kJ$
→$10.0 \,\mathrm{~mL}$ of $0.05\, \mathrm{M}\, \mathrm{KMnO}_{4}$ solution was consumed in a titration with $10.0\, \mathrm{~mL}$ of given oxalic acid dihydrate solution. The strength of given oxalic acid solution is $.....\,\times 10^{-2} \,\mathrm{~g} / \mathrm{L}$ (Round off to the nearest integer)
→The decomposition of $NH _{3}$ on $Pt$ surface is a zero order reaction. If the value of rate constant is $2 \times 10^{-4}\,mole $ $liter^{-1}\, sec ^{-1}$ The rate of appearance of $N _{2}$ and $H _{2}$ are respectively.
→Assertion : $NH_3$ is absorbed more readily over activated charcoal than $CO_2$.
→Reason : $NH_3$ is non-polar.