MCQ
Correct order of bond angle for bond will be


- A$Ph -OH > CH_3 -O -CH_3 > CH_3 -OH$
- ✓$CH_3 -O -CH_3 > Ph -OH > CH_3OH$
- C$CH_3 -OH > CH_3 -O -CH_3 > Ph -OH$
- D$CH_3 -O -CH_3 > CH_3OH > Ph -OH$

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$[A]$ $HClO_4$ is more acidic than $\mathrm{HClO}$ because of the resonance stabilization of its anion
$[B]$ $HClO_4$ is formed in the reaction between $Cl_2$ and $H_2 O$
$[C]$ The central atom in both $HClO_4$ and $HClO$ is $s p^3$ hybridized
$[D]$ The conjugate base of $HClO_4$ is weaker base than $H_2 O$
$(a)$ $NCl_3$ is formed when $Cl_2$ is present in excess.
$(b)$ $N_2$ is formed when $Cl_2$ is present in excess.
$(c)$ $N_2$ is formed when $NH_3$ is present in excess.
$(d)$ $NCl_3$ is formed when $NH_3$ is present in excess.
Correct option are
$C{H_2} = CH{(C{H_2})_8}COOH + HBr\xrightarrow{{{\text{peroxide}}}}$