MCQ
Correct order of bond angle in given species is
- A$SiO_4^{4-} > PCl_3 > NCl_3 > SbH_3 > H_2Te$
- B$SiO_4^{4-} > NCl_3 > PCl_3 > SbH_3 > H_2Te$
- ✓$SiO_4^{4-} > H_2Te > SbH_3 > PCl_3 > NCl_3$
- D$NCl_3 > PCl_3 > Si_4^{4-} > SbH_3 > H_2Te$
$Cl_2 (g) + 2H_2O (l) \to HCl(aq) + HOCl$
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$(A)\, F^-, Na^+, Mg^{+2}$ $(B) \,Ni, Cu, Zn$
$(C)\, N^{-3}, Cs^+, H^-$ $(D)\, Li, He, Be^{+2}$
If $(n=4)$ then di-carboxylic acid. would be known as
[Given $: h =6.626 \times 10^{-34}\,Js$,Mass of electron $=9.1 \times 10^{-31}$ ]