MCQ
Correct order of bond dissociation energy
- A$Br _{2} > Cl _{2}$
- B$F _{2} > Cl _{2}$
- C$I _{2} > F _{2}$
- D$F _{2} > I _{2}$
$Cl _{2}> Br _{2}> F _{2}> I _{2}$
Fluorine has very small size due to which inter-electronic repulsion is there between two fluorine atoms this results in the weaken bond.
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$F{e^2}+ \left( {aq} \right) + A{g^ + }\left( {aq} \right) \to F{e^{3 + }}\left( {aq} \right) + Ag\left( s \right)$
Given that:
$E_{Ag^+/Ag}^o = xV$
$E_{F{e^{2 + }}/Fe}^o = yV$
$E_{F{e^{3 + }}/Fe}^o = zV$