MCQ
Correct order of nucleophilicity for $SN^2$ reaction
  • A
    $\bar OH > {H_2}O > C{H_3}CO{O^ - }$
  • $\bar OH > C{H_3}CO{O^ - } > {H_2}O$
  • C
    ${H_2}O > C{H_3}CO{O^ - } > \bar OH$
  • D
    ${H_2}O = \bar OH = C{H_3}CO{O^ - }$

Answer

Correct option: B.
$\bar OH > C{H_3}CO{O^ - } > {H_2}O$
b

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

A solution of $0.1 M$ weak base $( B )$ is titrated with $0.1 M$ of a strong acid ($HA$). The variation of $pH$ of the solution with the volume of $HA$ added is shown in the figure below. What is the $p K_{ b }$ of the base? The neutralization reaction is given by $B + HA \rightarrow BH ^{+}+ A ^{-}$.
Assign $A, B, C, D$ from given type of reaction $KMn{O_4}\xrightarrow{\Delta }{K_2}Mn{O_4} + Mn{O_2} + {O_2} \uparrow $
The standard electrode potential for the two electrode ${A^ + }/A$ and ${B^ + }/B$ are respectively $0.5$  $V$ and $0.75$  $V$. The $emf$ of the given cell $A\,\,|\,\,{A^ + }(a = 1)\,\,||\,\,{B^ + }(a = 1)\,\,|\,\,B$ will be ........... $\mathrm{V}$
Neutralization of an acid with a base invariably results in the production of
$\begin{array}{*{20}{c}}
  {M{e_2}CH - CH - Me} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,} \\ 
  {\,\,\,\,\,\,\,\,OH} 
\end{array}\xrightarrow[{350{\,^o}C}]{{A{l_2}{O_3}}}(A)\xrightarrow[{(ii)\,AgOH}]{{(i)\,HI}}(B)$

Product $(B)$ of above reaction

Increasing value of magnetic moments of   $(I) \,\,[Fe(CN)_6]^{4-} $    $(II)\,\, [Fe(CN)_6]^{3-}$   $(III)\,\, [Cr(NH_3)_6]^{3+}$        $(IV)\,\, [Ni(H_2O)_4]^{2+}$  is
Products $A$  and $B$  formed in the following reactions are respectively

$[Figure]$  $\longrightarrow \,\,A\,\xrightarrow{{{C_6}{H_5}N{H_2}}}B$

As a result of $sp$ hybridization, we get
Lactic acid shows which type of isomerism
In the experiment set up for the measurement of EMF of a half cell using a reference electrode and a salt bridge, when the salt bridge is removed, the voltage