MCQ
Correct order of nucleophilicity for $SN^2$ reaction
- A$\bar OH > {H_2}O > C{H_3}CO{O^ - }$
- ✓$\bar OH > C{H_3}CO{O^ - } > {H_2}O$
- C${H_2}O > C{H_3}CO{O^ - } > \bar OH$
- D${H_2}O = \bar OH = C{H_3}CO{O^ - }$
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Product $(B)$ of above reaction
$[Figure]$ $\longrightarrow \,\,A\,\xrightarrow{{{C_6}{H_5}N{H_2}}}B$