MCQ
$\cos 1^\circ .\cos 2^\circ .\cos 3^\circ .........\cos 179^\circ = $
  • $0$
  • B
    $1$
  • C
    $2$
  • D
    $\frac{1}{2}$

Answer

Correct option: A.
$0$
a
(a) We know that one of the factor of the given expression is $\cos 90^\circ = 0$.

Therefore $\cos 1^\circ .\cos 2^\circ .\cos 3^\circ ...\cos 179^\circ = 0$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If $a\,.i\,=a\,.\,(i+j)=a\,.\,(i+j+k)$ , then $a = $
The least positive integer $n$ for which $\sqrt[3]{n+1}-\sqrt[3]{n} < \frac{1}{12}$ is
A point $z$ moves on Argand diagram in such a way that $|z -3i|$ $ = 2,$ then its locus will be
If the second term of the expansion ${\left[ {{a^{\frac{1}{{13}}}}\,\, + \,\,\frac{a}{{\sqrt {{a^{ - 1}}} }}} \right]^n}$ is $14a^{5/2}$ then the value of $\frac{{^n{C_3}}}{{^n{C_2}}}$ is :
If $y = {\tan ^{ - 1}}\left( {{{\sqrt x - x} \over {1 + {x^{3/2}}}}} \right),$ then $y'(1)$ is
The value of $\frac{1}{4} \,\,tan \frac{\pi}{8} +\frac{1}{8} \,\,tan \frac{\pi}{16}+\frac{1}{16} \,\,tan \frac{\pi}{32}+.\,.\,.\,\infty  $ terms is equal to-
On the intervl $ (1,3)$, the function $f(x) = 3x + {2 \over x}$ is
Let $F: R \rightarrow R$ be a thrice differentiable function. Suppose that $F (1)=0, F (3)=-4$ and $F^{\prime}( x )<0$ for all $x \in$ $(1 / 2,3)$. Let $f(x)=x F(x)$ for all $x \in R$.

$1.$ The correct statement$(s)$ is(are)

$(A)$ $f^{\prime}(1) < 0$

$(B)$ $f(2) < 0$

$(C)$ $f^{\prime}(x) \neq 0$ for any $x \in(1,3)$

$(D)$ $f^{\prime}(x)=0$ for some $x \in(1,3)$

$2.$ If $\int_1^3 x^2 F^{\prime}(x) d x=-12$ and $\int_1^3 x^3 F^{\prime \prime}(x) d x=40$, then the correct expression$(s)$ is(are)

$(A)$ $9 f^{\prime}(3)+f^{\prime}(1)-32=0$

$(B)$ $\int_1^3 f(x) d x=12$

$(C)$ $9 f^{\prime}(3)-f^{\prime}(1)+32=0$

$(D)$ $\int_1^3 f(x) d x=-12$

Give the answer question $1$ and $2.$

If $ABCD $ is a parallelogram, $\overrightarrow {AB} = 2\,i + 4\,j - 5\,k$ and $\overrightarrow {AD} = \,i + 2\,j + 3\,k,$ then the unit vector in the direction of $BD $ is
The equation of a straight line passing through $(3,2)$ and cutting an intercept of $2\,units$ between the lines $3x + 4y = 11$ and $3x + 4y = 1$ is :-