^ - 1 1 2 + 2 ^ - 1 1 2 is equal to - Vidyadip

MCQ

${\cos ^{ - 1}}\frac{1}{2} + 2{\sin ^{ - 1}}\frac{1}{2}$ is equal to

A
$\frac{\pi }{4}$
B
$\frac{\pi }{6}$
C
$\frac{\pi }{3}$
✓
$\frac{{2\pi }}{3}$

✓

Answer

Correct option: D.

$\frac{{2\pi }}{3}$

d
(d) ${\cos ^{ - 1}}\frac{1}{2} + 2{\sin ^{ - 1}}\frac{1}{2} $

$= \frac{\pi }{3} + \frac{{2\pi }}{6} = \frac{{2\pi }}{3}$.

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