^ -1 (1 2 ) 1. - 3 2. 3 3. 2 4. 2 3 - Vidyadip

Question

$\cos^{-1}\Big(\frac{1}{2}\Big)$

$-\frac{\pi}{3}$
$\frac{\pi}{3}$
$\frac{\pi}{2}$
$\frac{2\pi}{3}$

✓

Answer

$\frac{\pi}{3}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from INVERSE TRIGNOMETRIC FUNCTIONS→INVERSE TRIGNOMETRIC FUNCTIONS — all question types→MATHS STD 12 Science question papers→Rajasthan Board STD 12 Science question papers→Rajasthan Board question paper generator→

Similar questions

Minimize $Z=5 x+10$ y subject to $x+2 y \leq 120, x+y \geq 60, x-2 y \geq 0, x, y \geq 0$

The objective function Z = 4x + 3y can be maximised subjected to the constraints $ 3\text{x}+4\text{y}\leq24,$ $8\text{x}+6\text{y}\leq48,$ $\text{x}\leq5,\text{y}\leq6;\text{x},\text{y}\leq0.$

At only one point
At two points only.
At an infinite number of points.
None of these

Consider the following statements:

$\tan^{-1} 1+ \tan^{-1} (0.5) = \dfrac {\pi}2$
$\sin^{-1}{\cfrac{1}{3} }+ \cos^{-1}{\cfrac{1}{3}} =\cfrac{\pi}{2}$

Which of the above statements is/are correct ?

1 only
2 only
Both 1 and 2
Neither 1 nor 2

If $\vec{a} \times \vec{b}=\hat{i}-\hat{j}$ then the value of $\vec{b} \times \vec{a}$

The area of the region formed by $\text{x}^2+\text{y}^2-6\text{x}-4\text{y}+12\leq0,\text{ y}\leq\text{x}$ and $\text{x}\leq\frac{5}{2}$

A problem in Mathematics is given to three students whose chances of solving it are $\frac{1}{2}, \frac{1}{3}, \frac{1}{4}$ respectively. If the events of their solving the problem are independent then the probability that the problem will be solved, is

The cartesian equation of a line is $\frac{x+3}{2}=\frac{y-5}{4}=\frac{z+6}{2}$. The vector equation for the line is

If for the matrix $A=\left[\begin{array}{cc}\tan x & 1 \\ -1 & \tan x\end{array}\right], A+A^{\prime}=2 \sqrt{3},$ then the value of $x \in\left[0, \frac{\pi}{2}\right]$ is :

Which of the following differentials equation has y = x as one of its particular solution?

$\frac{\text{d}^{2}\text{y}}{\text{dx}^{2}}-\text{x}^{2}\frac{\text{dy}}{\text{dx}}+\text{xy}=\text{x}$
$\frac{\text{d}^{2}\text{y}}{\text{dx}^{2}}+\text{x}^{2}\frac{\text{dy}}{\text{dx}}+\text{xy}=\text{x}$
$\frac{\text{d}^{2}\text{y}}{\text{dx}^{2}}-\text{x}^{2}\frac{\text{dy}}{\text{dx}}+\text{xy}=\text{0}$
$\frac{\text{d}^{2}\text{y}}{\text{dx}^{2}}+\text{x}^{2}\frac{\text{dy}}{\text{dx}}+\text{xy}=\text{0}$

The restriction on n, k and p so that PY + WY will be define are:

k = 3, p = n
k is arbitrary, p = 2
p is arbitrary, k = 3
k = 2, p = 3