MCQ
Crystal field stablization energy for complex $[Co(CN)_6]^{-3}$ will be
- ✓$- 2.4{\Delta _0}\, + \,3P$
- B$+ 2.4{\Delta _0}\, + \,3P$
- C$- 3.6{\Delta _0}\, + \,3P$
- D$- 1.8{\Delta _0}\, + \,3P$
$\Delta= \text { no. of electrons in } t _{2 g } \cdot(-0.4)+\text { no. of electrons in } e _{ g }(0.6)$
$=6(-0.4)+0(0.6)$
$=-2.4 \Delta_0$
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$(a)$ Number of $S-S$ bonds in $H_2S_nO_6$ are $(n +1)$
$(b)$ When $F_2$ reacts with $H_2O$ it forms $HF,$ $O_2$ & $O_3.$
$(c)$ $XeF_6$ on hydrolysis shows disproportionation reaction
$(d)$ $Al$ metal on reacting with dilute $NaOH$ gives a white precipitate of $Al (OH)_3$ as a final product
$E^o_{Fe^{+2}/Fe} =-0.44\,V$ and $ E^o_{H^+ / O_2 / H_2O} =1.23\, V$
Calculate the $E^o_{cell}$ of the corrosion :- ............. $\mathrm{V}$