MCQ
$CuS{O_4}$ reacts with $KCN$ solution and forms
- A$Cu{(CN)_2}$
- B$Cu(CN)$
- C${K_2}\left[ {Cu{{(CN)}_4}} \right]$
- ✓${K_3}\left[ {Cu{{\left( {CN} \right)}_4}} \right]$
✓
Answer
Correct option: D.
${K_3}\left[ {Cu{{\left( {CN} \right)}_4}} \right]$
d
(d)$4KCN + CuS{O_4} \to \mathop {{K_3}[Cu{{(CN)}_4}]\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\limits_{{\rm{Potassium tetracyno cuprate}}} $
(d)$4KCN + CuS{O_4} \to \mathop {{K_3}[Cu{{(CN)}_4}]\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\limits_{{\rm{Potassium tetracyno cuprate}}} $
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