MCQ
$CuS{O_4}$ reacts with $KCN$ solution and forms:
- ✓${K_3}[Cu{(CN)_4}]$
- B$Cu(CN)$
- C$Cu{(CN)_2}$
- D${K_4}[Cu{(CN)_6}]$
✓
Answer
Correct option: A.
${K_3}[Cu{(CN)_4}]$
a
(a) $CuS{O_4}$ on reaction with $KCN$ gives ${K_3}[Cu{(CN)_4}]$
$2CuS{O_4} + 10KCN \to 2{K_3}[Cu{(CN)_4}] + 2{K_2}S{O_4} + {(CN)_2}$
(a) $CuS{O_4}$ on reaction with $KCN$ gives ${K_3}[Cu{(CN)_4}]$
$2CuS{O_4} + 10KCN \to 2{K_3}[Cu{(CN)_4}] + 2{K_2}S{O_4} + {(CN)_2}$
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