MCQ
Cycloalkane has the formula
- A${C_n}{H_{2n + 2}}$
- B${C_n}{H_{2n - 2}}$
- ✓${C_n}{H_{2n}}$
- D${C_{2n}}{H_2}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(II)$ (figure)
$(III)\, CH_3-N=CH_2$
$(IV)\, C_2H_5-CH=N-OH$

(Given atomic number $\mathrm{Sc}: 21, \mathrm{Ti}: 22, \mathrm{~V}: 23, \mathrm{Cr}$ : $24, \mathrm{Mn}: 25, \mathrm{Fe}: 26)$
$\begin{array}{*{20}{c}}
{\,\,\,\,\,OH\,\,\,\,\,\,\,OH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{C{H_3} - CH - C - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}\xrightarrow{{HI{O_4}}}(a) + (b)$
$(a)$ and $(b)$ respectively be :