d dx (x^2) = - Vidyadip

MCQ

${d \over {dx}}\{ \cos (\sin {x^2})\} = $

A
$\sin (\sin {x^2}).\cos {x^2}.2x$
✓
$ - \sin (\sin {x^2}).\cos {x^2}.2x$
C
$ - \sin (\sin {x^2}).{\cos ^2}x.2x$
D
None of these

✓

Answer

Correct option: B.

$ - \sin (\sin {x^2}).\cos {x^2}.2x$

b
(b) $\frac{d}{{dx}}\{ \cos (\sin {x^2})\} = - \sin (\sin {x^2})\cos {x^2}.2x$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 5. continuity and differentiation→5. continuity and differentiation — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

Let $R =\{( P , Q ) \mid P$ and $Q$ are at the same distance from the origin $\}$ be a relation, then the equivalence class of $(1,-1)$ is the set

The shortest distance between the line $y = x$ and the curve $y^2 = x - 2$ is

The maximum value of Z = 3x + 2y, subjected to $\text{x}+2\text{y}\leq2,\text{x}+2\text{y}\geq8;\text{x},\text{y}\geq0 $ is:

32
24
40
None of these

If $\left( {\vec a \times \vec b} \right) \times \vec c = \vec a \times \left( {\vec b \times \vec c} \right)$ where $\vec a, \vec b$ and $\vec c$ are any three vector such that $\vec a \cdot \vec b \ne 0,\vec b \cdot \vec c \ne 0$ then $\vec a$ and $\vec c$ are

The direction ratios of the diagonal of the cube joining the origin to the opposite corner are (when the 3 concurrent edges of the cube are coordinate axes).

$\frac{2}{\sqrt{3}},\frac{2}{3},\frac{2}{3}$
1, 1, 1
2, −2, 1
1, 2, 3

If the binary operation $\odot$ is defined on the set Q⁺ of all positive rational numbers by $\text{a}\odot\text{b}=\frac{\text{ab}}4$. Then, $3\odot\Big(\frac{1}5\odot\frac{1}2\Big)$ is equal to:

$\frac{3}{160}$
$\frac{5}{160}$
$\frac{3}{10}$
$\frac{3}{40}$

Find the value of $ {\sin ^{ - 1}}\left( 1 \right):$

$ \dfrac{\pi}{7}$
$ \dfrac{\pi}{6}$
$ \dfrac{\pi}{4}$
$ \dfrac{\pi}{2}$

If $\text{f(x)}=\frac{1}{1-\text{x}},$ then the set of points discontinuity of the function f(f(f(x))) is:

{1}
{0,1}
{-1, 1}
none of these

If $\vec{\text{a}}$ and $\vec{\text{b}}$ are unit vectors,then the greatest value of $\sqrt{3}\big|\vec{\text{a}}+\vec{\text{b}}\big|+\big|\vec{\text{a}}-\vec{\text{b}}\big|$ is:

$2$
$2\sqrt{2}$
$4$
$\text{None of these}$

Solution of the differential equation, $\frac{{dy}}{{dx}} = \frac{{1 - 2y - 4x}}{{1 + y + 2x}}$ is