MCQ
${d \over {dx}}{\cos ^{ - 1}}{{x - {x^{ - 1}}} \over {x + {x^{ - 1}}}} =$  
  • A
    ${1 \over {1 + {x^2}}}$
  • B
    ${{ - 1} \over {1 + {x^2}}}$
  • C
    ${2 \over {1 + {x^2}}}$
  • ${{ - 2} \over {1 + {x^2}}}$

Answer

Correct option: D.
${{ - 2} \over {1 + {x^2}}}$
d
(d) Putting $x = \cot \theta $

$y = {\cos ^{ - 1}}\left( {\frac{{x - {x^{ - 1}}}}{{x + {x^{ - 1}}}}} \right) = {\cos ^{ - 1}}\left( {\frac{{{x^2} - 1}}{{{x^2} + 1}}} \right)$

$ = {\cos ^{ - 1}}(\cos 2\theta ) = 2\theta $

$\Rightarrow \frac{{dy}}{{dx}} = \frac{{ - 2}}{{1 + {x^2}}}$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free