MCQ
${d \over {dx}}({e^x}\log \sin 2x) = $
  • ${e^x}(\log \sin 2x + 2\cot 2x)$
  • B
    ${e^x}(\log \cos 2x + 2\cot 2x)$
  • C
    ${e^x}(\log \cos 2x + \cot 2x)$
  • D
    None of these

Answer

Correct option: A.
${e^x}(\log \sin 2x + 2\cot 2x)$
a
(a) $\frac{d}{{dx}}({e^x}\log \sin 2x) = {e^x}\log \sin 2x + 2{e^x}\frac{1}{{\sin 2x}}\cos 2x$

$ = {e^x}\log \sin 2x + {e^x}2\cot 2x$$ = {e^x}(\log \sin 2x + 2\cot 2x).$

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