MCQ
${d \over {dx}}({e^x}\log \sin 2x) = $
- ✓${e^x}(\log \sin 2x + 2\cot 2x)$
- B${e^x}(\log \cos 2x + 2\cot 2x)$
- C${e^x}(\log \cos 2x + \cot 2x)$
- DNone of these
$ = {e^x}\log \sin 2x + {e^x}2\cot 2x$$ = {e^x}(\log \sin 2x + 2\cot 2x).$
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$\frac{\pi}{3}$
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$\frac{\pi}{12}$
$\frac{\pi}{2}$
$(A)$ $f (2)<1-\log _{ e } 2$ $(B)$ $f (2)>1-\log _{ e } 2$ $(C)$ $g(1)>1-\log _e 2$ $(D)$ $g(1)<1-\log _e 2$