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5. continuity and differentiation — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMaths5. continuity and differentiation1 Mark
MCQ
${d \over {dx}}\left[ {{{\tan }^{ - 1}}\sqrt {{{1 - \cos x} \over {1 + \cos x}}} } \right] = $
  • A
    $ - {1 \over 2}$
  • B
    $0$
  • ✓
    ${1 \over 2}$
  • D
    $1$
✓

Answer

Correct option: C.
${1 \over 2}$
c
(c) $\frac{d}{{dx}}\left[ {{{\tan }^{ - 1}}\sqrt {\frac{{1 - \cos x}}{{1 + \cos x}}} } \right] = \frac{d}{{dx}}\left[ {{{\tan }^{ - 1}}\tan \frac{x}{2}} \right] = \frac{1}{2}$.

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