MCQ
${d \over {dx}}{\log _{\sqrt x }}(1/x)$ is equal to
- A$ - {1 \over {2\sqrt x }}$
- B$-2$
- C$ - {1 \over {{x^2}\sqrt x }}$
- ✓$0$
$= \frac{{\log \left( {\frac{1}{x}} \right)}}{{\log \sqrt x }} $
$= \frac{{( - 1)\log x}}{{(1/2)\,\log x}} = - 2$
==> $f'(x) = 0$.
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Define $S _i=\int_{\frac{\pi}{8}}^{\frac{3 \pi}{8}} f( x ) \cdot g _i( x ) dx , i=1,2$
($1$) The value of $\frac{16 S _1}{\pi}$ is. . . . . .
($2$) The value of $\frac{48 S _2}{\pi^2}$ is. . . . .