MCQ
${d \over {dx}}(\log \tan x) = $
- A$2\sec 2x$
- ✓$2\,{\rm{cosec }}2x$
- C$\sec 2x$
- D${\rm{cosec}}\,2x$
✓
Answer
Correct option: B.
$2\,{\rm{cosec }}2x$
b
(b) $\frac{d}{{dx}}(\log \tan x) = \frac{1}{{\tan x}}{\sec ^2}x = \frac{{\cos x}}{{{{\cos }^2}x\sin x}}$
(b) $\frac{d}{{dx}}(\log \tan x) = \frac{1}{{\tan x}}{\sec ^2}x = \frac{{\cos x}}{{{{\cos }^2}x\sin x}}$
$ = \frac{2}{2}\frac{1}{{\cos x\sin x}} = 2\,{\rm{cosec}}\,2x$.
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