MCQ
${d \over {dx}}{({x^2} + \cos x)^4} = $
  • A
    $4({x^2} + \cos x)(2x - \sin x)$
  • B
    $4{({x^2} - \cos x)^3}(2x - \sin x)$
  • $4{({x^2} + \cos x)^3}(2x - \sin x)$
  • D
    $4{({x^2} + \cos x)^3}(2x + \sin x)$

Answer

Correct option: C.
$4{({x^2} + \cos x)^3}(2x - \sin x)$
c
(c) $\frac{d}{{dx}}{[{x^2} + \cos x]^4} = 4{[{x^2} + \cos x]^3}[2x - \sin x]$.

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