Question
Define electric field intensity and equipotential surface in current carrying conductor.
✓
Answer
Electric Field Intensity : In a current carrying conductor the ratio of potential difference applied across the ends of the conductor and the length of the conductor is equal to the electric field intensity at any point in the conductor. i.e.
$ E = V/l $
where $ V = $ potential difference and $ l = $ length.
Equipotential Surface : In a currnet carrying conductor electric currnet flows from the end of higher potential towards the end of lower potential. Hence electric potential decreases with increase the distance from the end of higher potential toward the end of lower potential but the electric potential at all points lying on any cross-section of the conductor is the same. Hence any cross-section of the conductor is equipotential surface.
$ E = V/l $
where $ V = $ potential difference and $ l = $ length.
Equipotential Surface : In a currnet carrying conductor electric currnet flows from the end of higher potential towards the end of lower potential. Hence electric potential decreases with increase the distance from the end of higher potential toward the end of lower potential but the electric potential at all points lying on any cross-section of the conductor is the same. Hence any cross-section of the conductor is equipotential surface.
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