- AAcetic acid
- BEthane
- ✓Ethylene
- DAcetylene
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$2 H _2( g )+2 NO ( g ) \rightarrow N _2( g )+2 H _2 O ( g )$
which following the mechanism given below:
$2 NO ( g ) \underset{ k _{-1}}{\stackrel{ k _1}{\rightleftharpoons}} N _2 O _2( g )$
$N _2 O _2( g )+ H _2( g ) \stackrel{ k _2}{\rightleftharpoons} N _2 O ( g )+ H _2 O ( g )$
$N _2 O ( g )+ H _2( g ) \stackrel{ k _3}{\rightleftharpoons} N _2( g )+ H _2 O ( g )$
(fast equilibrium)
(slow reaction)
(fast reaction)
The order of the reaction is
$(A)$ Reduction of $HCHO$
$(B)$ Oxidation of $HCHO$
$(C)$ Reduction of $PhCHO$
$(D)$ Oxidation of $Ph-CHO$
$CuI_{(s)} + e^{\circleddash} \to Cu_{(s)} + I^{\circleddash}_{(aq)}$ ; $E^o = -0.17\, V$
$Zn^{+2}_{(aq)} + 2e^{\circleddash} \to Zn_{(s)}$ ; $E^o = -0.76\, V$