Question
Derivative of$\sqrt{x^{-3}}$ at x = 4 is ___________ .
✓
Answer
self
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The area of the region bounded by the cartesian curve $y=f(x), x$-axis and the ordinates $x=a, x=b$ will be __________ .
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→A mirror in the shape of an ellipse represented by $\frac{\text{x}^2}{9}+-\frac{\text{y}^2}{4}=1$ was hanging on the wall. Arun and his sister were playing with ball inside the house, even their mother refused to do so. All of sudden, ball hit the mirror and got a scratch in the shape of line represented by $\frac{\text{x}}{3}+\frac{\text{y}}{2}=1$
Based on the above information, answer the following questions.
→Based on the above information, answer the following questions.
- Point(s) of intersection of ellipse and scratch (straight line) is (are).
- (0, 2), (3, 0)
- (2, 0), (3, 0)
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- (0, 3), (3, 0)
- Area of smaller region bounded by the ellipse and line is represented by.
- The value of $\frac{2}{3}\int\limits_{0}^{3}\sqrt{9-\text{x}^2}\text{dx}$ is.
- $\frac{\pi}{2}$
- $\pi$
- $\frac{3\pi}{2}$
- $\frac{\pi}{4}$
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- 0
- 1
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- $3\Big(\frac{\pi}{2}+1\Big)\text{ sq.units}$
- $\Big(\frac{\pi}{2}+1\Big)\text{ sq.units}$
- $\Big(\frac{\pi}{2}-1\Big)\text{ sq.units}$
- $3\Big(\frac{\pi}{2}-1\Big)\text{ sq.units}$
If $2 P ( A )= P ( B )=\frac{5}{12}$ and $P \left(\frac{A}{B}\right)=\frac{1}{5}$, then $P(A \cup B)$=______.
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If the feasible region for a LPP is _________, then the optimal value of the objective function Z = ax + by may or may not exist.
If the feasible region for a LPP is _________, then the optimal value of the objective function Z = ax + by may or may not exist.
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In a LPP, the linear inequalities or restrictions on the variables are called _________.
In a LPP, the linear inequalities or restrictions on the variables are called _________.
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The degree of the differential equation $\sqrt{1+\Big(\frac{\text{dy}}{\text{dx}}\Big)^2}=\text{x}$ is _________.
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If $A =\left[\begin{array}{l}2 \\ 5\end{array}\right], B =[7,8]$, then the value of $BA$ is $........$
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The vector equation of the line through the points (3, 4, -7) and (1, -1, 6) is __________.
The vector equation of the line through the points (3, 4, -7) and (1, -1, 6) is __________.