Question
Derive an expression for the power delivered by torque.
✓
Answer
Power delivered is the work done per unit time. IF we differentiate the expression for work done with respect to time, we get the instantaneous power $(P)$.
$ p =\frac{d w}{d t}=\tau \frac{d \theta}{d t} $
$ p =\tau d \omega $
$ p =\frac{d w}{d t}=\tau \frac{d \theta}{d t} $
$ p =\tau d \omega $
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Write down the comparison of $v_{r m s}, \bar{v}$ and $v_{m p}$.
→What is meant by Convection?
Explain projectile motion.
A cylinder of fixed capacity 44.8 litres contain helium gas at standard pressure and temperature. What is the amount of heat needed to raise the temperature of the gas by $15^{\circ} C ?\left( R =8.31 J mol { }^{-}\right.$ ${ }^1 K ^{-1}$ )
→The velocity time graph of a particle is given by –
Calculate distance and displacement of particle from given v – t graph. Specify the time for which particle undergone acceleration, retardation and moves with constant velocity. Calculate acceleration, retardation from given v – t graph. Draw acceleration-time graph of given v – t graph.
Calculate distance and displacement of particle from given v – t graph. Specify the time for which particle undergone acceleration, retardation and moves with constant velocity. Calculate acceleration, retardation from given v – t graph. Draw acceleration-time graph of given v – t graph.
The molecules of a given mass of a gas have rms velocity of $200 ms 1$ at $27^{\circ} C$ and $1.0 \times 10 s Nm ^{-}$ ${ }^2$ pressure. When the temperature and pressure of the gas are respectively. $127^{\circ} C$ and $0.05 \times$ $10 s Nm ^{-2}$. Find the rms velocity of its molecules in $ms ^{-1}$
→If the unit of force is 100N, unit of length is 10m and unit of time is 100s. What is the unit of Mass in this system of units ?
Define angular momentum. Give an expression for it.
The mass of a box measured by a grocer’s balance is 2.3 kg. Two gold pieces 20.15 g and 20.17 g are added to the box.
(i) What is the total mass of the box ?
(ii) The difference in masses of the pieces to correct significant figures.
(i) What is the total mass of the box ?
(ii) The difference in masses of the pieces to correct significant figures.
Is it necessary that work done in the motion of a body over a closed loop is zero for every force in nature? Why?