MCQ
Determine the value of $k$ for which the function $f(x)$ is continuous at $x=4$.
$f(x)=\left\{ \frac{x^2-16}{x-4}, x \neq 4 k, x=4 \right.$
  • A
    $2$
  • B
    $4$
  • C
    $6$
  • $8$

Answer

Correct option: D.
$8$
Since $f(x)$ is continuous at $x=4$. Therefore,
$\lim _{x \rightarrow 4} f(x)=f(4)$
$\Rightarrow \lim _{x \rightarrow 4} f(x)=k \quad[\because f(4)=k]$
$\Rightarrow \lim _{x \rightarrow 4} \frac{x^2-16}{x-4}=k$
$\Rightarrow \lim _{x \rightarrow 4} \frac{(x-4)(x+4)}{x-4}=k$
$\Rightarrow \lim _{x \rightarrow 4}(x+4)=k$
$\Rightarrow k=8$

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