MCQ
Determine the value of $k$ for which the function $f(x)$ is continuous at $x=4$.
$f(x)=\left\{ \frac{x^2-16}{x-4}, x \neq 4 k, x=4 \right.$
$f(x)=\left\{ \frac{x^2-16}{x-4}, x \neq 4 k, x=4 \right.$
- A$2$
- B$4$
- C$6$
- ✓$8$
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