- A$ - \mathop C\limits_| = O$
- B$-C \equiv N$
- C$-NO_2$
- ✓$-CH =CH-$
For example $\to -CH = CH-, - N = N -$
It can not be reduced following gps.
$\begin{array}{*{20}{c}}
{O\,\,\,\,\,\,\,\,N\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{||\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{ \to - C - , - C - , - N = O, - C \equiv N - NC,}
\end{array}$
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Assertion $A :$ The amphoteric nature of water is explained by using Lewis acid/base concept.
Reason $R$ : Water acts as an acid with $NH _{3}$ and as a base with $H _{2} S$.
In the light of the above statements choose the correct answer from the options given below :
$\text{P}_4+3\text{OH}^-+3\text{H}_2\text{O}\xrightarrow{ \ \ \ \ \ \ \ }\text{PH}_3+3\text{H}_2\text{PO}^-_2$

$C{H_3} - \mathop {\mathop {\mathop {\mathop C\limits^| }\limits^{Cl} - }\limits_{|\,\,\,\,} }\limits_{OH} C{H_2}CH = CHC{H_3}$