Codes: $ \quad P \quad Q \quad R \quad S $
- ✓$\quad 1 \quad 3 \quad 4 \quad 2 $
- B$\quad 2 \quad 4 \quad 3 \quad 1 $
- C$\quad 4 \quad 1 \quad 2 \quad 3 $
- D$\quad 3 \quad 2 \quad 1 \quad 4 $
Codes: $ \quad P \quad Q \quad R \quad S $
Four pathways for reactions are given :
$Image$
with $3 \& 4$, but not with $1 \& 2$.
$\therefore \quad 1: P$ or $S \quad 3: Q$ or $R$
$2$: $P$ or $S \quad 4: Q$ or $R$
combining these options gives
$1$: $P$ , $2$: $S$ , $3$: $Q$ , $4$: $R$
I cannot but help commenting that such questions are those which make $IIT-JEE$ what it is. A good motivation for students to keep thinking while studying .
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$S{O_2}C{l_2}(g) \rightleftharpoons S{O_2}(g) + C{l_2}(g)$
$CO(g) + C{l_2}(g) \rightleftharpoons COC{l_2}(g)$
on adding more $SO_2$ at equilibrium what will happen?
$\mathrm{Sn}^{4+}, \mathrm{Sn}^{2+}, \mathrm{Pb}^{2+}, \mathrm{Tl}^{3+}, \mathrm{Pb}^{4+}, \mathrm{Tl}^{+}$
Here en $=$ ethylene diamine