Differential equation of the function c+4 y x=0 is - Vidyadip

MCQ

Differential equation of the function $c+4 y x=0$ is

A
$x y+\frac{ d y}{ d x}=0$
✓
$x \frac{ d y}{ d x}+y=0$
C
$\frac{ d y}{ d x}-4 x y=0$
D
$x \frac{ d y}{ d x}+1=0$

✓

Answer

Correct option: B.

$x \frac{ d y}{ d x}+y=0$

$x \frac{ d y}{ d x}+y=0$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from Question Bank [2022]→Question Bank [2022] — all question types→Maths STD 12 Science question papers→Maharashtra Board STD 12 Science question papers→Maharashtra Board question paper generator→

Similar questions

The p.m.f. of a r.v. X is
$P(x)=\left\{\begin{array}{cc}k x^2 ; & x=1,2,3,4 \\
0 ; & \text { otherwise }\end{array}\right.$
Then, $E(X)=$

If $\int\frac{1}{5+4\sin\text{x}}\text{ dx}=\text{A}\tan^{-1}\Big(\text{B}\tan\frac{\pi}{2}+\frac{4}{3}\Big)+\text{C},$ then:

If $P$ and $q$ are the order and degree of the differention $\text{y}\frac{\text{dy}}{\text{dx}}+\text{x}^{3}\frac{\text{d}^{2}\text{y}}{\text{dx}^{3}}+\text{xy}=\cos\text{x}$ then:

The area of the region bounded by Y -axis, $y=\cos x$ and $y=\sin x ; 0 \leq x \leq \frac{\pi}{2}$ is

Equation of a line passing through point $(1,2,-4)$ and perpendicular to lines $\frac{x-8}{3}=\frac{y+19}{-16}=\frac{z-10}{7}$ and $\frac{x-15}{3}=\frac{y-29}{8}=\frac{z-5}{-5}$ is

If $x^2+y^2+z^2= r ^2$, then $\tan ^{-1}\left(\frac{x y}{z r}\right)+\tan ^{-1}\left(\frac{y z}{x r}\right)+\tan ^{-1}\left(\frac{z x}{y r}\right)=$

If $[x]$ denotes the greatest integer less than or equal to $x$, then the value of $\int_0^2(|x-2|+[x]) d x$ is equal to

For any vector $\bar{x}$ the value of $(\bar{x} \times \hat{ i })^2+(\bar{x} \times \hat{ j })^2+(\bar{x} \times \hat{ k })^2$ is equal to

The integral value of $\int_{-2}^0\left[x^3+3 x^2+3 x+3+(x+1) \cos (x+1)\right] d x$ is

Let $f (x)=x-[x]$, for every real number $x$, where $[x]$ is integral part of $x$.
Then, $\int_{-1}^1 f(x) d x$ is