MCQ
Differential equation of $y = \sec ({\tan ^{ - 1}}x)$ is
- A$(1 + {x^2})\frac{{dy}}{{dx}} = y + x$
- B$(1 + {x^2})\frac{{dy}}{{dx}} = y - x$
- ✓$(1 + {x^2})\frac{{dy}}{{dx}} = xy$
- D$(1 + {x^2})\frac{{dy}}{{dx}} = \frac{x}{y}$
$\frac{{dy}}{{dx}} = \sec ({\tan ^{ - 1}}x)\tan ({\tan ^{ - 1}}x)\,.\,\frac{1}{{1 + {x^2}}}$$ = \frac{{xy}}{{1 + {x^2}}}$
==> $(1 + {x^2})\frac{{dy}}{{dx}} = xy$.
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$E_1=\{A \in S: \operatorname{det} A=0\} \text { and }$ $E_2=\{A \in S: \text { sum of entries of } A \text { is } 7\}.$ If a matrix is chosen at random from $S$, then the conditional probability $P\left(E_1 \mid E_2\right)$ equals. . . . . . . .
where $[. ]$ denotes greatest integer function is equal to :