Question
Diffrentiate the following w.r.t.x
$\tan [\cos (\sin x)]$
$\tan [\cos (\sin x)]$
$\frac{d y}{d x}=\frac{d}{d x}\{\tan [\cos (\sin x)]\}$
$\begin{aligned} & =\sec ^2[\cos (\sin x)] \cdot \frac{d}{d x}[\cos (\sin x)] \\ & =\sec ^2[\cos (\sin x)] \cdot[-\sin (\sin x)] \cdot \frac{d}{d x}(\sin x) \\ & =-\sec ^2[\cos (\sin x)] \cdot \sin (\sin x) \cdot \cos x .\end{aligned}$
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