MCQ
Dilute nitric acid on reaction with $Ag$ liberates
- ✓$NO$ gas
- B$NO_2$ gas
- C$N_2$ gas
- D$O_2$ gas
$3 \mathrm{Ag}+4 \mathrm{HNO}_{3}(\mathrm{dil}) \rightarrow 3 \mathrm{AgNO}_{3}+2 \mathrm{H}_{2} \mathrm{O}+\mathrm{NO} \uparrow$
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$CH_3COOH + PCl_5 \longrightarrow (A)$ $\xrightarrow[(2){{H}_{2}}O]{(1)\,C{{H}_{3}}MgBr}\left( B \right)$ Product $B$ would be
($A$) Formic acid
($B$) Formaldehyde
($C$) Benzaldehyde
($D$) Acetone
Choose the correct answer from the options given below :
$\begin{array}{*{20}{c}}
{C{H_3}\,\,\,} \\
{|\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - CHC{H_3}} \\
{\,|\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,H\,\,\,\,\,\,\,Br}
\end{array}$ $\xrightarrow{{C{H_3}OH}}$