MCQ
Displacement vs. time curve for a particle executing $\text{S.H.M.}$ is shown in Fig. Choose the correct statements:
  • A
    Phase of the oscillator is same at $t = 0 s$ and $t = 2 s.$
  • B
    Phase of the oscillator is same at $t = 2 s$ and $t = 6 s.$
  • C
    Phase of the oscillator is same at $t = 1 s$ and $t = 5 s.$
  • Both $B$ and $C$

Answer

Correct option: D.
Both $B$ and $C$
Two particles are said to be in same phases if the mode of vibration is same i.e, their distance will be $\text{n}\lambda(\text{n}=1,2,3...)$
Distance between particles at $t = 0$ and $t = 2$ is $\frac{\lambda}{2}.$
So, articles are not in same phase.

As from figure the particles at $t = 2 \sec$ are at distance $\lambda$,
so are in same phase.
Particles at $t = 1, t = 7$ are the distance $\lambda+\frac{\lambda}{2}=\frac{3\lambda}{2}$ so are not in phase.
Particles at $t = 1$ and $5\sec$ are at distance $= \lambda$ so are in same phase.

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