Distance of the point ( , , ) from y-axis is - Vidyadip

MCQ

Distance of the point $(\alpha, \beta, \gamma)$ from $y$-axis is

A
$\sqrt{\alpha^2+\gamma^2}$
B
$|\beta|+|\gamma|$
C
$|\beta|$
D
$\beta$

✓

Answer

(a) $\sqrt{\alpha^2+\gamma^2}$
Explanation: The foot of perpendicular from point $P(\alpha, \beta, \gamma)$ on y -axis is $Q(0, \beta, 0)$
$\therefore$ Required distance, $P Q=\sqrt{(\alpha-0)^2+(\beta-\beta)^2+(\gamma-0)^2}=\sqrt{\alpha^2+\gamma^2}$

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