1 (2 + x) ^4 = - Vidyadip

MCQ

$\frac{1}{{{{(2 + x)}^4}}} = $

A
$\frac{1}{2}\left( {1 - 2x + \frac{5}{2}{x^2} - ....} \right)$
✓
$\frac{1}{{16}}\left( {1 - 2x + \frac{5}{2}{x^2} - ....} \right)$
C
$\frac{1}{{16}}\left( {1 + 2x + \frac{5}{2}{x^2} + ....} \right)$
D
$\frac{1}{2}\left( {1 + 2x + \frac{5}{2}{x^2} + ....} \right)$

✓

Answer

Correct option: B.

$\frac{1}{{16}}\left( {1 - 2x + \frac{5}{2}{x^2} - ....} \right)$

b
(b) ${(x + 2)^{ - 4}} = {2^{ - 4}}{\left[ {1 + \frac{x}{2}} \right]^{ - 4}} = \frac{1}{{16}}\left[ {1 - 2x + \frac{5}{2}{x^2} - ....} \right]$

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