MCQ
$\frac{\sin 3 A-\cos \left(\frac{\pi}{2}-A\right)}{\cos A+\cos (\pi+3 A)}=$
  • A
    tan A
  • B
    cot A
  • C
    tan 2A
  • cot 2A

Answer

Correct option: D.
cot 2A
(D)
$\frac{\sin 3 A-\cos \left(\frac{\pi}{2}-A\right)}{\cos A+\cos (\pi+3 A)}=\frac{\sin 3 A-\sin A}{\cos A - \cos 3 A}$
$=\frac{2 \cos 2 A \sin A }{2 \sin 2 A \sin A }$
$= cot 2A$

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