Gujarat BoardEnglish MediumSTD 8MATHSFactorization1 Mark
MCQ
Divide $36(a^2bc + ab^2c + abc^2)$ by $9abc$
A
$4abc + 4abc + 4abc$
B
$36a + 36b + 36c$
✓
$4(a + b + c)$
D
$4abc + 4ab^2c + 4abc^2$
✓
Answer
Correct option: C.
$4(a + b + c)$
C. $4(a + b + c)$ Solution:
Write this division as a fraction$\frac{36(\text{a}^2\text{bc}+\text{ab}^2\text{c}+\text{abc}^2)}{9\text{abc}}$
Take out the common factors from the numerator.
$\Rightarrow\frac{9\times4\text{abc}(\text{a+b+c})}{9\text{abc}}$
$\Rightarrow4(\text{a+b+c})$
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