Question
Divide and write the quotient and the remainder.
$\left(-48 p^4\right) \div\left(-9 p^2\right)$
$\left(-48 p^4\right) \div\left(-9 p^2\right)$
✓
Answer
$\left(-48 p^4\right) \div\left(-9 p^2\right)$
$\begin{aligned} & \therefore \text { Quotient }=\frac{16}{3} \mathrm{p}^2 \\ & \text { Remainder }=0\end{aligned}$
$\begin{aligned} & \therefore \text { Quotient }=\frac{16}{3} \mathrm{p}^2 \\ & \text { Remainder }=0\end{aligned}$
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