Question
Divide the sum of $\frac{65}{12}$ and $\frac{8}{3}$ by their difference.
✓
Answer
Sum of $\frac{65}{12}$ and $\frac{8}{3}$
$=\frac{65}{12}+\frac{8}{3}$
$=\frac{65+32}{12}$
$=\frac{97}{12}$
Difference of $\frac{65}{12}$ and $\frac{8}{3}$
$=\frac{65}{12}-\frac{8}{3}$
$=\frac{65-32}{12}$
$=\frac{33}{12}$
$\therefore\frac{97}{12}\div\frac{33}{12}$
$=\frac{97}{12}\times\frac{12}{33}$
$=\frac{97}{33}$
$=\frac{65}{12}+\frac{8}{3}$
$=\frac{65+32}{12}$
$=\frac{97}{12}$
Difference of $\frac{65}{12}$ and $\frac{8}{3}$
$=\frac{65}{12}-\frac{8}{3}$
$=\frac{65-32}{12}$
$=\frac{33}{12}$
$\therefore\frac{97}{12}\div\frac{33}{12}$
$=\frac{97}{12}\times\frac{12}{33}$
$=\frac{97}{33}$
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