MCQ
Dobernier traids is :-
- A$Na, K, Rb$
- B$Mg, S, As$
- ✓$Cl, Br, I$
- D$P, S, As$
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$C{H_3}COH\xrightarrow[{{\text{Zn(Hg)/Conc}}{\text{. HCI}}}]{{\left[ H \right]}}C{H_3}C{H_3}$ is
(Given : Atomic Number: F :9, $Cl : 17, Na =11$, $Mg =12, Al =13, K =19, Ca =20, Sc =21$ )


$[I]$ Only $A, B$ and $C$ react with $1\,M\,HCl$ to give $H_2\,(g)$
$[II]$ When $C$ is added to solutions of the other metal ions, metallic $B$ and $D$ are formed.
$[III]$ Metal $C$ does not reduce $A^{n+}$